MATH SOLVE

2 months ago

Q:
# What is the probability of getting exactly 5 “heads” in 10 coin flips ?

Accepted Solution

A:

There are [tex]\dbinom{10}5=\dfrac{10!}{5!(10-5)!}=252[/tex] ways of getting exactly 5 heads in 10 tosses. There are [tex]2^{10}=1024[/tex] possible outcomes. So the probability of getting exactly 5 heads is[tex]\dfrac{252}{1024}=\dfrac{63}{256}\approx24.61\%[/tex]